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Thermodynamics of Computation

Editing A cost/speed/reliability tradeoff to erasing

From Thermodynamics of Computation

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|doi=10.1007/978-3-319-21819-9_14
 
|doi=10.1007/978-3-319-21819-9_14
 
|isbn=9783319218182
 
|isbn=9783319218182
|arxiv=https://arxiv.org/abs/1410.1710
 
 
|scopus=2-s2.0-84943625259
 
|scopus=2-s2.0-84943625259
 
|pui=606383559
 
|pui=606383559
|abstract=We present a KL-control treatment of the fundamental problem of erasing a bit. We introduce notions of "reliability" of information storage via a reliability timescale <math>\tau_r</math>, and "speed" of erasing via an erasing timescale <math>\tau_e</math>. Our problem formulation captures the tradeoff between speed, reliability, and the Kullback-Leibler (KL) cost required to erase a bit. We show that rapid erasing of a reliable bit costs at least <math>\log 2 - \log\left(1 - \operatorname{e}^{-\frac{\tau_e}{\tau_r}}\right) > \log 2</math>, which goes to <math>\frac{1}{2} \log\frac{2\tau_r}{\tau_e}</math> when <math>\tau_r>>\tau_e</math>.
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|abstract=We present a KL-control treatment of the fundamental problem of erasing a bit. We introduce notions of "reliability" of information storage via a reliability timescale $\tau_r$, and "speed" of erasing via an erasing timescale $\tau_e$. Our problem formulation captures the tradeoff between speed, reliability, and the Kullback-Leibler (KL) cost required to erase a bit. We show that rapid erasing of a reliable bit costs at least $\log 2 - \log\left(1 - \operatorname{e}^{-\frac{\tau_e}{\tau_r}}\right) > \log 2$, which goes to $\frac{1}{2} \log\frac{2\tau_r}{\tau_e}$ when $\tau_r>>\tau_e$.
 
|Mendeley link=http://www.mendeley.com/research/costspeedreliability-tradeoff-erasing
 
|Mendeley link=http://www.mendeley.com/research/costspeedreliability-tradeoff-erasing
 
|pages=192-201
 
|pages=192-201

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